Question

If entalpy of formation of c2h4 and c2h6 are x1 and x2 respectively then heat of hydrogenation of c2h4 is

Answer 1

Answer:

The heat of hydrogenation of ethene is equal to the difference between enthalpy of formation of ethane from the enthalpy of formation of ethene.

Explanation:

Enthalpy of formation of ethene:

$2C+2H_2\rightarrow C_2H_4,\Delta H_f=x_1$

Enthalpy of formation of ethane:

$2C+3H_2\rightarrow C_2H_6,\Delta H_f=x_2$

On subtracting (2) from (1) , we get:

$C_2H_4+H_2\rightarrow C_2H_6,\Delta H_{Hydrogenation}=?$

$\Delta H_{Hydrogenation}=x_2-x_1$

The heat of hydrogenation of ethene is equal to the difference between enthalpy of formation of ethane from the enthalpy of formation of ethene.

Answer 2

Answer:

The heat of hydrogenation of ethene is equal to the difference between enthalpy of formation of ethane from the enthalpy of formation of ethene.

Explanation:

Enthalpy of formation of ethene:

2C+2H_2\rightarrow C_2H_4,\Delta H_f=x_12C+2H

2

→C

2

H

4

,ΔH

f

=x

1

Enthalpy of formation of ethane:

2C+3H_2\rightarrow C_2H_6,\Delta H_f=x_22C+3H

2

→C

2

H

6

,ΔH

f

=x

2

On subtracting (2) from (1) , we get:

C_2H_4+H_2\rightarrow C_2H_6,\Delta H_{Hydrogenation}=?C

2

H

4

+H

2

→C

2

H

6

,ΔH

Hydrogenation

=?

\Delta H_{Hydrogenation}=x_2-x_1ΔH

Hydrogenation

=x

2

−x

1

The heat of hydrogenation of ethene is equal to the difference between enthalpy of formation of ethane from the enthalpy of formation of ethene.