Question

If enthalpies of formation for C2H4(9), CO2(g) and
H2O(l) at 25°C and 1 atm pressure are 52, -394
and -286 kJ/mol respectively, then enthalpy of
combustion of C2H4(9) will​

Answer 1

Answer:

Explanation:the chemical reaction for the above equation is

c2h4(g)+3o2(g) gives 2co2(g)+2h2o(g) then enthalpy of combustion of C2H4= ENTHALPY OF FORMATION OF PRODUCTS- REACTANTS =[(2x-394)+(2x-286)]- [(52+0)]= [-788-572]-52=-1412kj/mol