Question

If equal mass of O2 and O3 are taken in separate
container, then the ratio of number of atoms is
(1) 1:1
(2) 1:2
(3) 1:3
(4) 1:4​

Answer 1

Explanation:

let equal masses of O2&O3 be x gram

no. of moles = given gram mass/molar mass

no. of moles of O2= x/32moles

no. of molecules of O2=(x/32)N [here N represent avagadro's no.]

no. of atoms of O2=(x/32)N*2

=(x/16)N atoms

no. of moles of O3= x/48moles

no. of molecules of O3=(x/48)N [here N represent avagadro's no.]

no. of atoms of O3=(x/48)N*3

=(x/16)N atoms

therefore

ratio of no. of atoms of O2 to no. of atoms of O3

=[(x/16)N atoms]/[(x/16)N atoms]

=1/1

therefore ratio=1:1