Question

If equal masses of N2and O2 are taken, the ratio of no.of molecules in these gases would be?
(a) 1:1 (b) 7:8 (c) 8:7 (d) 28:32

Please answer with full and step-by-step explanation. ​​

Answer 1

Answer:

see the attachment given here

answer-c

Answer 2

Given:

Equal masses of nitrogen gas and oxygen gas are taken.

To find:

The ratio of no. of molecules in these gases.

Step-by-step explanation:

Step 1 of 2

Let the masses of both nitrogen gas and oxygen gas be 'm'.

The number of moles can be used to calculate the number of molecules.

The number of moles of nitrogen gas are: $\frac{m}{28}$

The number of moles of oxygen gas are: $\frac{m}{32}$

Step 2 of 2

1 mole of any substance will have $6.022*10^{23}$ molecules.

$\frac{m}{28}$ moles of nitrogen gas will have $\frac{m}{28}*6.022*10^{23}$ molecules.

$\frac{m}{32}$ moles of oxygen gas will have $\frac{m}{32}*6.022*10^{23}$ molecules.

The ratio of molecules will be:

$\frac{m}{28}*6.022*10^{23}: \frac{m}{32}*6.022*10^{23}\\=\frac{32}{28} \\=\frac{8}{7}$

Therefore, option (c) 8:7 is correct.