if equal to 3 by 5 then tan theta equal to
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ΔABC be a right angled at B
Let ∠ACB=θ
Given that, sin θ = 3/5
AB/AC = 3/5
Let AB = 3x
then AC = 5x
In right angled ΔABC,
By Pythagoras theorem,
We get
(5x)
2
=(3x)
2
+BC
2
BC
2
=(5x)
2
−(3x)
2
BC
2
=(2x)
2
BC=4x
(i) cos θ = Base/ Hypotenuse
= BC / AC
= 4x /5x
= 4/5
(ii) tan θ = perpendicular/Base
= AB/BC
= 3x/4x
=3/4
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