Math, asked by pkkmr0202, 7 months ago

If equation (a? + 2)2 – (b + 4)(a4 + 3a2 + 2) + (b + 3)(a2 + 1)2 = 0 has atleast one real solution, then value of 'b' can be
-2
-3
2​

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Answered by prakharverma214
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If equation (a? + 2)2 – (b + 4)(a4 + 3a2 + 2) + (b + 3)(a2 + 1)2 = 0 has atleast one real solution, then value of 'b' ca

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