Question

If equation (re-2r+1)x2 + (r - 3r + 2)x-(r2 + 4r + 3) = 0 is identity in x, then value of r is :-​

Answer 1

Answer:

Solution



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Correct option is

C

−5050

x3−2x2+4x+5074=0      (given)

r1+r2+r3=a−b=1−(−2)=2     ---(i)

r1r2+r2r3+r3r1=ac=14=4   ---(ii)

r1r2r3=a−d=1−5074=−5074      ---(iii)

(r1+2)(r2+2)(r3+2)=(r1+2)