Question

If equations of a projectile projected at angle θ with horizontal are following
x = 15t (m)
y = 15t – 5t2 (m), (where x and y are co-ordinates) then the initial velocity is given by

Answer 1

Answer:

Equation of trajectory is Y=Xtanθ−2u2gX2(1+tan2θ)

On Comparison with given equation 

xtanθ=4t

⇒(3t)tanθ=4t

⇒tanθ=34

θ=tan−1(4/3)≈530