Question

if equilibrium constant for N2 +O2 = 2NO is 4×10^-4 . Kc for NO = ½N2 + ½O2 at same temperature is ?​

Answer 1

Answer:

Kc = 0.5×10^2

Explanation:

For

N2 + O2 = 2NO

(Kc)1 = 4×10^-4

As the given reaction changes to NO = 1/2N2 +1/2O2,

(Kc)2 = 1/(√Kc1)

(Kc)2 = 1/(√4×10^-4)

(Kc)2 = 1/(2×10^-2)

(Kc)2 = 0.5 × 10^2

I hope this helps:)