Question

If equilibrium constant is 2 atm at 300 K then the standard free energy change at 300 K and 1 atm pressure is ​

Answer 1

Answer:

Solution:

When both PbCO3 and MgCO3 are present in solution

Suppose solubility of PbCO3 is xmolL−1 and that of MgCO3 is ymolL−1 then,

pbCO3↽−−⇀pb2+x+CO2−3x+y

MgCO3↽−−⇀Mg2+y+CO2−3x+y

Ksp(pbCO3)Ksp(MgCO3)=x(x+y)y(x+y)=xy

=1.5×10−151.0×10−15=1.5

Thus, x=1.5y

Ksp(pbCO3)=x(x+y)=1.5×10−15

∴1.5y(1.5y+y)=1.5×10−15

or 3.75y2=1.5×10−15

y=(1.5×10−153.75)1/2=2×10−8

Now, x=1.5y

Explanation:

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