Question

if error in measurement of P6 Momentum is 2 per. and that of mass is 1% find percentage error in measurement of kinetic energy​

Answer 1

Answer:

Explanation: hope u get it

Thank you

Answer 2

Kinetic energy = mv²/2

And momentum p = mv

So v= p/m

→ K = p²/2m

→ p²= K× 2m......(1)

Taking log on both sides,

logp² =log(K×2m)

→ 2logp = logK + log2m

→ logK = - log2m +2logp

Differentiating both sides with K,

d logK/dK = -dlog2m/dK + d 2logp/dK

→|dK/dK|max = -2|1/100| + 2|2/100|

→ |dK/dK| max = -2×0.001 + 0.004

=0.002

Maximum % error in the kinetic energy is 0.002×100%=2%