Question

If escape velocity from the earth’s surface is 11.2 km/sec. Then escape velocity from a planet of mass same as that of earth but radius one fourth as that of earth is

Answer 1

The escape velocity from the Earth’s surface is 11.2 km/s. What is the value for a planet having double the radius and eight times the mass of Earth?

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4 ANSWERS



Gajanan Samant

Answered Nov 14, 2017 · Author has 242answers and 133.3k answer views

The standard formula for escape velocity is

ve=2GMR−−−−−√ve=2GMR

For comparison of two escape velocities -

vplanetvearth=MplanetMearthRearthRplanet−−−−−−−−−−−−√vplanetvearth=MplanetMearthRearthRplanet

Given info for the planet -

Rplanet=2RearthRplanet=2Rearth

Mplanet=8MearthMplanet=8Mearth

Therefore -

vplanetvearth=8MearthMearthRearth2Rearth−−−−−−−−−−−−−√vplanetvearth=8MearthMearthRearth2Rearth

vplanetvearth=8112−−−√vplanetvearth=8112

vplanetvearth=41−−√vplanetvearth=41

vplanet=2vearthvplanet=2vearth

vplanet=2∗11.2vplanet=2∗11.2

vplanet