Question

If Euler's formula is defined as F+V=E+2 where F is no of faces ,V is no of vertices and E represent no of Edges of a given solid using it find the no of faces of tetrahedron having verticesas 4 and 6 edges​

Answer 1

Answer:

The formula is,

F+V=E+2

where,

F=no of faces =?

V=no of vertices =4

E=no of edges =6

so according to the formula,

F+4=6+2

F+4=8

F=8-4

F=4

so, a tetrahedron has 4 faces, 4 vertices and 6 edges

Hope this helps