Question

if ever side of triangle is doubled ,then area of triangle increase. %​

Answer 1

Step-by-step explanation:

Heron's formula states for a triangle with sides of lengths a,b,c

A=

[s∗(s−a)∗(s−b)∗(s−c)]

where s = (a+b+c)/2

If you double the sides A=

[2s∗(2s−2a)∗(2s−2b)∗(2s−2c)]

= 4*A=

[s∗(s−a)∗(s−b)∗(s−c)]

= 4*A

The increase in area is 4*A-A = 3*A so the

Answer (C) 300%

Answer 2

Answer: UR REQUIRED SOLUTION ;-

heron's formula states for a triangle with sides of length a, b , c

A = [ s × ( s - a ) × ( s -b ) × ( s - c ) ]

where s = ( a + b +c ) / 2

if you doubled the sides A = [ 2s × ( 2s - 2a ) × ( 2s - 2b ) × ( 2 s - 2c )]

⇒ 4 × A =  [ s × ( s -a ) × ( s - b )× ( s -c ) ]

= 4 × A  

the increase area is 4 × A - A = 3 × A

so , the answer is 300 %

Step-by-step explanation:

itz akansha .