Math, asked by seemamittal991986, 9 months ago

If every side of a trianlge is doubled, then

increase in the area of the triangle is :​

Answers

Answered by mohit810275133
0

HEY MATE HERE IS YOUR ANSWR

Heron's formula states for a triangle with sides of lengths a,b,c

A=

[s∗(s−a)∗(s−b)∗(s−c)]

where s = (a+b+c)/2

If you double the sides A=

[2s∗(2s−2a)∗(2s−2b)∗(2s−2c)]

= 4*A=

[s∗(s−a)∗(s−b)∗(s−c)]

= 4*A

The increase in area is 4*A-A = 3*A so the

Answer (C) 300%

Answered by MysteriousAryan
0

Answer:

A = ½bh

On doubling the sides.

A = ½(2b × 2h) = 2bh

The area increases 4 times the original.

Increase in area = 2 - ½ = 1½ = 3/2

Increase percentage = 3/2÷½×100=300%

Verification

Original triangle, A = ½bh = ½(5 × 6) = 15 cm²

Increased triangle, A = 2bh = 2×5×6 = 60 cm²

By times

Area of Increased triangle = 15 × 4 = 60 cm²

Area of increases triangle by percentage increase = 15×400/100 = 60 cm²

Similar questions