If exterior angle of an isosceles triangle is 1100 and its interior opposite angles are equal, then each equal angle measures
A.65 degree
B.60 degree
C.50 degree
D.55 degree
Answers
Answered by
0
Answer:
d) 55°
Explanation:
110°+x=180°
x=70°
sum of all sides of triangle =180°
so, 70°+y+z=180°
(here y=z given)
2y=110°
y=55°
Answered by
0
Answer:
Using the theorem that if the side of a triangle is produced then the interior angle is equal to the sum of two interior opposite angles of the triangle.
Let ΔABC be a triangle where the side BC is produced.
By the theorem we have
∠A+∠B=100
o
…………..(1)
It is given that the interior opposite angles are equal i.e., ∠A=∠B.
∴ Equation (1) becomes
2∠A=100
o
⇒∠A=50
o
⇒∠B=50
o
Using angle sum property of a triangle,
Sum of all angles of a triangle =180
o
⇒∠A+∠B+∠C=180
o
⇒100+∠C=180
o
[from (1)]
⇒∠C=180
o
−100
o
⇒∠C=80
o
.
Hence ∠A=50
o
∠B=50
o
∠C=80
o
.
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