Question

if
Exu:- Find the quadratic polynomial
Zeroes are half and minus half​

Answer 1

Step-by-step explanation:

$zeroes \: : \: \frac{1}{2} \: and \: - \frac{1}{2} \\ format : \\ {x}^{2} - (sum \: of \: zeroes)x + (product \: of \: zeroes) \\ = {x }^{2} - ( \frac{1}{2} - \frac{1}{2} )x + ( \frac{1}{2} \times - \frac{1}{2} ) \\ = {x}^{2} - 0x + \frac{( - 1)}{4} \\ = {x}^{2} - \frac{1}{4} \\ it \: can \: be \: also \: written \: as \\ \frac{1}{4} (4 {x}^{2} - 1)$