Question

if f:[0,1] arrow [-1,1] defined by f(x)=x², then f is​

Answer 1

Given, function f:R→R such that f(x)=1+x2, 

Let A and B be two sets of real numbers.

Let x1,x2∈A such that f(x1)=f(x2).

⇒1+x12=1+x22⇒x12−x22=0⇒(x1−x2)(x1+x2)=0

⇒x1=±x2. Thus f(x1)=f(x2) does not imply that x1=x2.