Math, asked by jaswicaosoe59, 9 months ago

if f= {(1,2), (2,-3), (3,-1)}, then find 2f, 2+f, f^2, rootf

Please give step by step explanation.​

Answers

Answered by sky6064
3

Answer:

the answer is 2f= 72, 2+f= (-34), f^2= 1296 and rootf= (-3)

Step-by-step explanation:

f={ (1×2) (2×-3) (3× -1)}

f={ 2× (-6) × (-3)}

f={12 × (-3)}

f={-36}

2f= f × 2

2f= -36 × 2

2f= 72

2+f= 2 + f

2+f= 2 + (-36)

2+f= -34

f^2= f×f

f^2= (-36) × (-36)

f^2=1296

rootf= root(-36)

rootf= root(-3)

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