if f= {(1,2), (2,-3), (3,-1)}, then find 2f, 2+f, f^2, rootf
Please give step by step explanation.
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Answer:
the answer is 2f= 72, 2+f= (-34), f^2= 1296 and rootf= (-3)
Step-by-step explanation:
f={ (1×2) (2×-3) (3× -1)}
f={ 2× (-6) × (-3)}
f={12 × (-3)}
f={-36}
2f= f × 2
2f= -36 × 2
2f= 72
2+f= 2 + f
2+f= 2 + (-36)
2+f= -34
f^2= f×f
f^2= (-36) × (-36)
f^2=1296
rootf= root(-36)
rootf= root(-3)
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