If f={(1,2),(2,-3),(3,-1)}, then find (i)2f (ii)f² (iii)f+2 (iv)√f
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Answer:
Given that
f = {(1, 2), (2, -3), (3, -1)}
According to it , we have
f(1) = 2 , f(2) = - 3 , f(3) = - 1
i. 2f
Solution: 2f(1) = 2(2) = 4 , 2f(2) = 2(- 3) = -6 , 2f(3) = 2(- 1) = -2
ii. 2 + f
Solution: 2 + f(1) = 2 + 2 = 4 , 2 + f(2) = 2 + ( - 3 ) = 2 - 3 = - 1 ,
2 + f(3) = 2 + (- 1) = 2 - 1 = 1
iii. f²
Solution: f^2(1) = 2^2 = 4 , f^2(2) = (- 3)^2 = 9 , f^2(3) = (- 1)^2 = 1
iv. √f
Solution:
\begin{gathered}\sqrt{f(1)} = \sqrt{2} \\\sqrt{f(2)} = \sqrt{-3} \\\sqrt{f(3)} =\sqrt{-1}\end{gathered}
f(1)
=
2
f(2)
=
−3
f(3)
=
−1
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