Question

if f(1+x)=x²+1 , then f(2-h) is​

Answer 1

Step-by-step explanation:

Given If f(1+x) = x²+1 , then f(2-h) is

• Given f (1 + x) = x^2 + 1 ---------------1
•      Let 1 + x = y
• So x = y – 1
• Now putting the value of x in eqn 1
• Therefore f(1 + y – 1) = (y – 1)^2 + 1
• So f (y) = (y – 1)^2 + 1
• Now putting y = 2 – h we get
• Now  f (2 – h) = (2 – h – 1)^2 + 1
•                       = (1 – h)^2 + 1
• We know that (a – b)^2 = a^2 + b^2 – 2ab
•                      = 1 + h^2 – 2 h + 1

                    = h^2 - 2h + 2

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Answer 2

Answer:

Step-by-step explanation:

Given If f(1+x) = x²+1 , then f(2-h) is

Given f (1 + x) = x^2 + 1 ---------------1

    Let 1 + x = y

So x = y – 1

Now putting the value of x in eqn 1

Therefore f(1 + y – 1) = (y – 1)^2 + 1

So f (y) = (y – 1)^2 + 1

Now putting y = 2 – h we get

Now  f (2 – h) = (2 – h – 1)^2 + 1

                     = (1 – h)^2 + 1

We know that (a – b)^2 = a^2 + b^2 – 2ab

                    = 1 + h^2 – 2 h + 1

                   = h^2 - 2h + 2