If f (2) =
1
2+1
2x
I (1 - 1)
(2+1)
3.x (x - 1) = (x - 1)(x - 2) (x + 1) x (- 1)
then f (2018) is equal to
(A) 0
(B) 1
(C) 2018
(D) -2018
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