Question

If f(2x + 3) = 6x + 7, show that (fof^-1)(x) is an identity function,
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Answer 1

Answer:

Now, let y = (4x + 3)/(6x - 4)

=> y * (6x - 4) = 4x + 3

=> 6xy - 4y = 4x + 3

=> 6xy - 4y - 4x = 3

=> 6xy - 4x = 3 + 4y

=> x(6y - 4) = 4y + 3

=> x = (4y + 3)/(6y - 4)

So, f-1 (x) = (4x + 3)/(6x -