If f(4)=1, f(5)=-1, f(8)=1, f(10)=-1, then using Lagrange's formula, the value of f(6) is equal to
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then there exists atleast one real root of the equation f(x) = 0 in open interval (a,b). ... f(-2)= -5 + 2 Sin 2 ,f(-1)= -4 + 2 sin 1 ... 10. Using Lagrange Interpolation find the value of y at x= 8.
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