if f:A-B,g:B-A and f={(1,a),(2,c),(4,d),(3,b)} g'={(2,a),(4,b),(1,c),(3,d)} verify (gof)'=f'og'
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Step-by-step explanation:
Given f={(1,a),(2,c),(4,d),(3,b)} and g−1={(2,a),(4,b),(1,c),(3,d)}.
Then we have f−¹={(a,1),(c,2),(d,4),(b,3)} and g={(a,2),(b,4),(c,1),(d,3)}.
Now gof={(1,2),(2,1),(4,3),(3,4)}
⇒(gof)−1={(2,1),(1,2),(3,4),(4,3)}......(1).
Again f−¹og−¹={(2,1),(4,3),(1,2),(3,4)}={(2,1),(1,2),(3,4),(4,3)}....(2).
From (1) and (2) we have (gof)−¹=f−¹og−¹,
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