Question

If f(a)= log(2 + a/2- a)
for 0 < a < 2, then find 1/2f(8a/4+ a square)​

Answer 1

Answer:

Step-by-step explanation:

Since f(a)=log(2−a2+a​), we have

21​f(4+a28a​)=21​log⎝⎜⎜⎜⎛​2−4+a28a​2+4+a28a​​⎠⎟⎟⎟⎞​=21​log[8+2a2−8a8+2a2+8a​]=21​log[4+a2−4a4+a2+4a​]=21​log(2−a2+a​)2

Applying logxa=alogxHence,

21​f(4+a28a​)=f(a)x, we get

21​log(2−a2+a​)2=22​log(2−a2+a​)