If f and g are real valued functions defined by f(x) = 2x–1 and g(x) = x2
then find
i) (3f –2g) (x)
Answers
Answered by
3
=3f-2g
=3(2x-1)-2x²
= -2x²+6x-3
now multiply these by
=-2x³+6x²-3x
Answered by
1
Step-by-step explanation:
[ 3(2x-1) - 2(x2)] (x)
[6x-3-4x](x)
2x²-3
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