Question

If F = ax + bt2

+ c where F is force, x is distance and t is time. Then what is dimension

of 2 bt/ axc?​

Answer 1

Answer:

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Answer 2

Answer:

$[MLT^{-2} ]$

Explanation:

F=ax + $bt^{2}$ +c

∵ F = $[MLT^{-2} ]$

∴ ax= $bt^{2}$= c =  $[MLT^{-2} ]$

now,

$\frac{axc}{bt^{2} }$ = $\frac{[MLT^{-2} ] [MLT^{-2} ]}{[MLT^{-2} ]}$

     = $[MLT^{-2} ]$