Question

if f is a signum function then a real valued f(-20)=?​

Answer 1

$\huge{\mathfrak{\underline{\red{Answer!}}}}$

The value of f(x) at x=5 is 1

Step-by-step explanation:

Conept used:

Signum function:

$f(x)=\frac{x}{|x|}\:if\:x\neq0</p><p>\:\:\:\:=0\:\:\:if\:x=0$

clearly,

Range of f is { -1, 0, 1}

At x=5,

$f(x)=\frac{5}{|5|}$

$f(x)=\frac{5}{5}$

$f(x)=1$