Question

if f(m)=3m^2+5m-7 then find,f(x+2), f(2/3), f(-5)​

Answer 1

Step-by-step explanation:

$f(m) = 3 {m}^{2} + 5m - 7 - - (i) \\ subtitute \: by \: (x + 2) \: in \: (i) \\ f(x + 2) = 3 {(x + 2)}^{2} + 5(x + 2) - 7 \\ = 3( {x}^{2} + 4x + 4) + 5x + 10 - 7 \\ = 3 {x}^{2} + 12x + 12 + 5x + 3 \\ = 3 {x}^{2} + 17x + 15 \\ subtitute \: by \: ( \frac{2}{3} ) \: in \: (i) \\ f(\frac{2}{3}) = 3 {(\frac{2}{3})}^{2} + 5 \times \frac{2}{3} - 7 \\ = 3 \times \frac{4}{9} + \frac{10}{3} - 7 \\ = \frac{4}{3 } + \frac{10}{3} - 7 \\ = \frac{4 + 10 - 21}{3} \\ = \frac{ - 7}{3} \\subtitute \: by \: ( - 5) \: in \: (i) \\ f( - 5) = 3 {( - 5)}^{2} + 5( - 5) - 7 \\ = 3 \times 25 - 25 - 7 \\ = 75 -32 \\ = 43$

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