If f(m)= m²-3m+1
Find f(2+h)-f(2)/h
h≠0
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Answer:
f(2+h) = (2+h)² – 3(2+h) ± 1
= 4+4h+h²– 6 – 3h + 1
=h² + h – 1
f (2) = 2²–3(2) + 1 = 4 - 6 + 1 = – 1
f(2+h)–f/h = (h²+h–1)–(–1)/h
h(h + 1)/h
h+1. [h not equal to 0]
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