If f of x is equal to 5 x square minus 4x minus 1 then 0 of f of x - 1 is
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f(x)= 5x^2 - 4x - 1 = 0 --> A)
f(x-1) = ?
Solution
Equation A can be written as,
5x^2 - 4x - 1 = 0 --> B)
now we need to put x = x-1 in equation B),
5(x-1)^2 - 4*(x-1) -1 =0
now applying (a-b)^2=a^2+b^2-2ab,
(x-1)^2=x^2+1-2x
5(x²-x+1)- 4x+ 4 -1=0
5x² -5x +5 -4x +4 -1=0
5x² -9x +8=0
so that,
f(x-1)= 5x² -9x +8=0
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