if f:R–R be defined as f(x)=(3―x3)1/3 then find fof(x)
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f(x) = (3-3x)1/3
fof(x)= f(f(x))
= f((3-3x)1/3)
= {3-3(3-3x)1/3}1/3
= 1-1(3-3x)1/3
= 1-1(1-x)
= 1-1+x
= x
#########################
fof(x)= f(f(x))
= f((3-3x)1/3)
= {3-3(3-3x)1/3}1/3
= 1-1(3-3x)1/3
= 1-1(1-x)
= 1-1+x
= x
#########################
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