If F:R-R,f(x)=x+3 and G:R-R,g(x)=2x findGof(3) and Gof(5)
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Step-by-step explanation:
We have f(x)=x3+3 & g(x)=2x+1
∴f−1(x)=(x−3)1/3 & g−1(x)=2(x−1)
∵f−1og−1(x)=f−1[g−1(x)]
∴f−1og−1(23)=f−1[g−1(23)]=f−1(11)
=(11−3)1/3=(8)1/3=2
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