Question

if f:R-R,g:R-R are defined by f(x)=2x-3 g(x)=x³+5 then find (f⁰g)‐¹(x)​

Answer 1

Answer:

Since f(x)=2x+3,

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x 2

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x 2 +7,

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x 2 +7,g(2+3x)=8⇒(2x+3)

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x 2 +7,g(2+3x)=8⇒(2x+3) 2

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x 2 +7,g(2+3x)=8⇒(2x+3) 2 +7=8

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x 2 +7,g(2+3x)=8⇒(2x+3) 2 +7=8⇒2x+3=±1

Since f(x)=2x+3,g[f(x)]=8⇒g(2x+3)=8.Also since g(x)=x 2 +7,g(2+3x)=8⇒(2x+3) 2 +7=8⇒2x+3=±1⇒x=−1 or −2