If f : R → R is defined by f(x) = 2x-3. Prove that f is a bijection and find its inverse.
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A N S W E R :
F is bijective!
STEP BY STEP EXPLANATION :
Recall that F:A→B is a bijection only if F is
injective: F(x)=F(y)⇒x=y , and
surjective: ∀b∈B there is some a∈A such that F(a)=b .
So, is f an injection?
Take x,y∈IR and assume that f(x)=f(y) . Therefore 2x−3=2y−3 . We can cancel out the 3 and divide by 2 , then we get x=y .
Is f a surjection?
This is a trivial case since the two sets of the function are the set of real numbers. Every x∈IR is bound to a value defined by 2x−3 .
Therefore: F is bijective!
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3
Answer:
How many numbers are there between 100 and 500 with the digits 0, 1, 2, 3, 4, 5 if
(i) repetition of digits allowed
(ii) the repetition of digits is not allowed
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