If f: R to R is defined by f(x) =x square -5x,then the inverse image set of {-6}is
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If f: R to R is defined by f(x) =x square -5x,then the inverse image set of {-6}is
For inverse image set of {−6}
For inverse image set of {−6}we have, x
For inverse image set of {−6}we have, x 2
For inverse image set of {−6}we have, x 2 −5x=−6
For inverse image set of {−6}we have, x 2 −5x=−6x
For inverse image set of {−6}we have, x 2 −5x=−6x 2
For inverse image set of {−6}we have, x 2 −5x=−6x 2 −5x+6=0
For inverse image set of {−6}we have, x 2 −5x=−6x 2 −5x+6=0x
For inverse image set of {−6}we have, x 2 −5x=−6x 2 −5x+6=0x 2
For inverse image set of {−6}we have, x 2 −5x=−6x 2 −5x+6=0x 2 −3x−2x+6=0
For inverse image set of {−6}we have, x 2 −5x=−6x 2 −5x+6=0x 2 −3x−2x+6=0(x−2)(x−3)=0
For inverse image set of {−6}we have, x 2 −5x=−6x 2 −5x+6=0x 2 −3x−2x+6=0(x−2)(x−3)=0Hence, the set is {3,2}
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