if f:Rto R and g:RtoR defined by f(x)=2x+mod x then f(3x)-f(-x)-4x=
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f(3x)=2×3x+mod3x
=6x+3x
=9x.....equation.1
f(-x) =-2x+mod-x
=-2x+x
=-x.......equation.2
then f(3x)-f(-x)-4x = 9x-(-x)-4x
= 9x+x-4x
=6x .
=6x+3x
=9x.....equation.1
f(-x) =-2x+mod-x
=-2x+x
=-x.......equation.2
then f(3x)-f(-x)-4x = 9x-(-x)-4x
= 9x+x-4x
=6x .
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