If f(t) = 4+2 – 3t+6, find f(4).
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Answer:
2a−[4b−4a−(3b−
2a+2b
ˉ
)]
2a−[4b−4a−(3b−2(a+b))]
2a−[4b−4a−(3b−2a−2b)]
2a−[4b−4a−(b−2a)]
2a−[4b−4a−b+2a)]
2a−[4b−6a−b)]
2a−[4b−6a+b]
2a−[5b−6a]
2a−5b+6a
8a−5b
Step-by-step explanation:
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