Question

if f(t)=4t²-3t+6, find f(0),f(4),f(-5)​

Answer 1

Step-by-step explanation:

4t2-3t+6 is given equation

f(0)=4(0)2-3(0)+6

f(0)=6

f(4)=4(4)2-3(4)+6

f(4)=64-12+6

f(4)=58

f(-5)=4(-5)2-3(-5)+6

f(-5)=100+15+6

f(-5)=121