Question

If f(t)=4tpower2 -3t+6 [find f(0), f(-1) , f(2)]​

Answer 1

6,13,16

Step-by-step explanation:

Given that f(t)=4t^2-3t+6

f(0)=4(0)^2-3(0)+6

f(0)=0-0+6 [any number multiple with "0" means that value also "0"]

f(0)=6

f(-1)=4(-1)^2-3(-1)+6

f(-1)=4+3+6

f(-1)=13.

f(2)=4(2)^2-3(2)+6

f(2)=[4×4]-6+6

f(2)=16. [-6+6=0]

I HOPE THIS ANSWER WILL BE USEFUL TO YOU....