Question

If f(t)= (t^3-1) g(t)= 1 h(t)= -t^2 then find the value of fohog at t= -3

Answer 1

Answer:

f(h(g(t)))=f(h(g(-3)))

g(-3)=1

f(h(1))=f(-1^2)=f(1)=1^3-1

=1-1=0

Step-by-step explanation:

Answer 2

Answer:

0 is answer dear friend