Question

if f(t)=t^3+√2t^2+3√2t-1, then evaluate (2√2)​

Answer 1

given:f(t)=t^3+√2t^2+3√2t-1

f(t)= t( t^2+√2t+3√2)-1

put 2√2 where written t

now, f(t)= 2√2{ (2√2)^2+ √2(2√2)+3√2}-1= 24√2-11