Question

If f(t) = t³ + √2t² + 3√2t - 1, then evaluate f(2√2)

Answer 1

(2√2)^3+√2(2√2)^2+3√2×√2-1
=16√2+8√2+12-1
=24√2+11
=33.94+11
=44.94

Answer 2

Answer:

$({2 \sqrt{2} }^{3}) + { \sqrt{2}(2 \sqrt{2}) }^{2} + 3 \sqrt{2} (2 \sqrt{2}) - 1 \\ 16 \sqrt{2 } + \sqrt[8]{2} + 12 - 1 \\ \sqrt[24]{2} + 11 \\ 33.94 + 11 \\ 44.94$

Step-by-step explanation:

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