Question

if f(x) = 1/1–x, g(x)=f(f(x)) and h(x)= f(f(f(x))). then for x not= 0,1 the value of f(x).g(x).h(x)=?

Answer 1

as f(X)=1/1-x

here g(X)=1/1-(1/1-x)=X-1/X,

so h(X)=f(g(X))=X

now

the answer is -1.