Question

if f(x)=1+sec²x,then the least value of f(x) is
1)2
2)greater than 2
3)less than 2
4)greater than 1 and less than 2

answer with correct option and solution will be selected as Brainliest answer

and spams please

pls don't forget to give solution​

Answer 1

$\huge{\blue{\boxed{\boxed{\boxed{\pink{\underline{\underline{\mathfrak{\red{♡ĂnSwer♡}}}}}}}}}}$

as we know that

$\huge\boxed{\fcolorbox}{1+tan^2=sec^2}}}$

for the least value of (1 + sec^2)

we will add 1 both side

we get ...

2+ tan^2 = 1 + sec^2

for the least value tan^2 will be zero..

therefore ur answer will be ... 2

I hope it will helps u...

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