if f(x)= (1-sin2x+cos2x)/2cos2x find value of f(11)f (34)
kritartha:
what is 11 here it is degree or simple 11 tell me first
degree
ok
i give you solution now
Answers
Answered by
29
please go through this solution
if you understand then thanks me and mark as a brainliest.
if you understand then thanks me and mark as a brainliest.
Attachments:
please mark as a brainliest
if you have any doubt please tell me\
and if you undertsand
then please mark as abrainliest
sorry but please tell me how to mark an answer as brainliest ... i don't know
i did it.. thanx a lot :)
please click on marks as a brainlist
ok
or give me 5star and thaks
Answered by
22
f (x)=(1-sin2x+cos2x)/2cos2x
=(2cos^2x-2sinx.cosx)/2cos2x
=(cos^2x-sinx.cosx)/(cos^2x-sin^2x)
=cosx/(cosx+sinx)
now
f (11)=cos11/(cos11+sin11)
f (34)=cos34/(cos34+sin34)
f (11) f (34)=cos11.cos34/(cos11+sin11)(cos34+sin34)
=cos11.cos34/(cos11+cos79)(cos34+cos56)
=cos11.cos34/(2cos45.cos34)(2cos45.cos11)
=1/(4cos^2(45))=1/4x2=1/2
=(2cos^2x-2sinx.cosx)/2cos2x
=(cos^2x-sinx.cosx)/(cos^2x-sin^2x)
=cosx/(cosx+sinx)
now
f (11)=cos11/(cos11+sin11)
f (34)=cos34/(cos34+sin34)
f (11) f (34)=cos11.cos34/(cos11+sin11)(cos34+sin34)
=cos11.cos34/(cos11+cos79)(cos34+cos56)
=cos11.cos34/(2cos45.cos34)(2cos45.cos11)
=1/(4cos^2(45))=1/4x2=1/2
I hope this is helpful
please mark as brainliest
yes it is Thanx a lot
so please mark brainliest
sorry but I've already marked another one as brainliest....sorry
its okay
Similar questions