If f(x)=(1/x +1)/(1/x-1) The value of f(x)+f(-x) is
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f(x)=x−1x+1
fof(x)=f(x)−1f(x)+1=x−1x+1−1x−1x+1+1=x+1−x+1x+1+x−1=x
i)(fofof)(x)=f(fof(x))=f(x)=x−1x+1
ii)(fofofof)(x)=fof(fof(x))=fof(x)=x
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