if f(x)=1-x/1+x then f[f(cos2θ)]
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Step-by-step explanation:
(1-cos(2))/(1+cos(2)) can be written nicely as [2 sin² (1)]/[2 cos² (1)] which is tan²(1)
Now, (1-tan²(1))/(1+tan²(1)). The top is cos(2)sec²(1) and the bottom is just sec²(1), so the secants cancel leaving, just cos(2)
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