if f(x-1)=x^2+2 then find f(t+2)
Answers
Answered by
0
f(x-1) = x² +2 =x²-2x +1 +2x - 2 +3
= (x-1)² +2(x-1) +3
So,
f(t+2) = (t+2)² +2(t+2) +3
= t² +4t +4 +2t+4+3
= t² +6t +11 (ans)
= (x-1)² +2(x-1) +3
So,
f(t+2) = (t+2)² +2(t+2) +3
= t² +4t +4 +2t+4+3
= t² +6t +11 (ans)
Similar questions